|
|
Log in / Subscribe / Register

OT: The # operator?

OT: The # operator?

Posted May 31, 2006 6:33 UTC (Wed) by Los__D (guest, #15263)
In reply to: OT: The # operator? by Los__D
Parent article: The kernel lock validator

Doh, just preprocessor argument->string conversion, nevermind, too early in the morning for me ;)


to post comments


Copyright © 2026, Eklektix, Inc.
Comments and public postings are copyrighted by their creators.
Linux is a registered trademark of Linus Torvalds