So a splice based copy will be zero memory copies, and two DMA "copies"
I presume "copies" is in quotes because you agree with me that the DMA operations are not copies in the sense we're talking about. (If they were, a "zero-copy" file read wouldn't be zero-copy, and moving data from kernel file data cache to user space would be two copies (kernel memory to register, register to user memory)).
However, the combination of the two DMAs constitutes one disk copy. A disk copy is an instance of replicating data from one place on a disk to another, just as a memory copy is an instance of replicating data from one place in memory to another. And it's worth talking about because it takes time. If you could truly do a zero-copy copy, that would be remarkable. As it stands, "zero-copy copy" is just a trick of words in which you change the definition of copy in the middle of the sentence.
A normal copy contains the same number of DMA operations, but includes a memory copy.
Actually, the most normal file copy includes two memory copies -- from kernel file data cache of the source file to user space buffer, and from that buffer to the other file's kernel file data cache. With mmap, you can get it down to one, and with direct I/O you can get to zero.
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