oops

oops

Posted Mar 29, 2013 16:14 UTC (Fri) by HelloWorld (guest, #56129)
In reply to: Still no fixed template syntax by HelloWorld
Parent article: A look at C++14, part 1

Actually, it would become

template〈typename T〉
std::enable_if〈T::foo〈42〉::value, T〉::type bla();

(notice the lack of the template keyword before foo.

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