>> (Note that any fraction with a factor larger than two in the denominator requires infinite significant bits, which is obviously much more than 52. This is where most of the reputation originates. However, it doesn't affect integers.)
> not really. It's rather, any factor with a denominator that is not in the part of the set 2^n, (or with decimal floating point, 2^n * 5^m)
I was referring to the prime factors; any number of the form 2^n * 5^m with naturals n and m (!= 0) has prime factors 2 and 5. A number with a prime factor of 3 or 7, for example, would not terminate in either binary or decimal. However, your description is equivalent.