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It's a comma operator.It's a comma operator.Posted Apr 15, 2012 23:47 UTC (Sun) by alison (✭ supporter ✭, #63752)In reply to: It's a comma operator. by xoddam Parent article: Linux kernel design patterns - part 1
Posted Jun 11, 2009 0:56 UTC (Thu) by xoddam notes
"the infamous http://en.wikipedia.org/wiki/Comma_operator".
Humorously, I just had a look at the Wikipedia article. "Huh, I thought I understood the comma operator!" Copied the code in question out, compiled and tested it, and sure enough the latest revision to the article was erroneous. So yeah, I guess the Comma Operator causes some confusion!
-- Alison
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