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Evolution of shells in Linux (developerWorks)Evolution of shells in Linux (developerWorks)Posted Dec 9, 2011 20:13 UTC (Fri) by HelloWorld (guest, #56129)In reply to: Evolution of shells in Linux (developerWorks) by nybble41 Parent article: Evolution of shells in Linux (developerWorks)
> Technically it *will* work, but only because the value of the variable is output in the first iteration of the loop,
No, the loop starts at 1 instead of 0.
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Evolution of shells in Linux (developerWorks) Posted Dec 9, 2011 20:25 UTC (Fri) by nybble41 (subscriber, #55106) [Link]
Hm. You're right, which is strange since both arrays and characters are zero-indexed (except for $@). Perhaps that loop was written for a different shell entirely? It's certainly not necessary in reasonably modern implementations (i.e. within the last decade) of bash.
Evolution of shells in Linux (developerWorks) Posted Dec 10, 2011 3:34 UTC (Sat) by mathstuf (subscriber, #69389) [Link]
Nope, I was a typo. Somehow I missed that it just printed something on the first iteration, and nothing on the rest... Not sure how I forgot about printf either.
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