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Syntax flubsSyntax flubsPosted Jan 30, 2010 10:52 UTC (Sat) by ncm (subscriber, #165)In reply to: Syntax flubs by tjc Parent article: GCC to merge Go support
No, it is no problem. Of course Go is not bound to match C's operators in any
case, but if they chose to be so bound, they could use "@" for the purpose. As could, indeed, C or C++. I.e., those languages could also fix the problem, even at this late date. They can be excused for not doing so, but Go cannot.
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Syntax flubs Posted Feb 4, 2010 18:25 UTC (Thu) by tjc (subscriber, #137) [Link] I agree, using '@' as an indirection operator would work. But it looks funny, especially as a postfix operator. I would probably get used to it.I better like the idea of separating declaration syntax from expression syntax and using '*' as a postfix pointer declarator and '[]' as an infix[1] indirection operator, like this: var p *[10]int; var a [10]*int; [p][0] = 1; [a[0]] = 1; I guess I could call this "square lisp" syntax. :) [1] This really isn't infix, since the operand is infix, not the operator, but I don't know the correct term for this form.
Syntax flubs Posted Feb 4, 2010 22:51 UTC (Thu) by anselm (subscriber, #2796) [Link] [1] This really isn't infix, since the operand is infix, not the operator, but I don't know the correct term for this form. Outfix?
Syntax flubs Posted Feb 7, 2010 1:44 UTC (Sun) by tjc (subscriber, #137) [Link] Outfix?You are indeed correct! http://www.abstractmath.org/MM/MMFunctionValue.htm#_Toc223234910 It seems obvious in retrospect. Thanks.
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