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The Kernel Hacker's Bookshelf: Ultimate Physical Limits of ComputationThe Kernel Hacker's Bookshelf: Ultimate Physical Limits of ComputationPosted Jun 19, 2008 10:44 UTC (Thu) by enodev (guest, #14913)Parent article: The Kernel Hacker's Bookshelf: Ultimate Physical Limits of Computation
Why doesn't the author take the volume of a modern cpu or hard disk into account when calculating the storage/calculation power of a current laptop? I mean the data storing volume of a 2.5" hard disk platter is about (3.14*6cm^2*50um) = 6e-4 dm^2 ~= 1e-3 dm^3. So only 16 orders of magnitude to go... . Same applies for the volume of a cpu die. Or do I miss something?
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The Kernel Hacker's Bookshelf: Ultimate Physical Limits of Computation Posted Jun 19, 2008 17:22 UTC (Thu) by vaurora (guest, #38407) [Link] In the original article, the author makes it much more clear that we are assuming nothing about what the technology of computers in the future looks like. In particular, we're not assuming that the storage of the computer is compartmentalized into a small box containing spinning rust-covered disks. :) All the calculations are based solely on the mass and volume of the computer, with no assumptions about distribution.
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