Posted Mar 19, 2008 21:11 UTC (Wed) by vmole (guest, #111)
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Because it's not a matter of narrow vs. wide, or using something "narrower than (void *)". If the function specification says "This vararg list is terminated by null character pointer", then, by the standard, you have to pass something equivalent to "(char *) 0", and "(void *) 0" isn't. The idea of a "void *" being generic is that variables of type "void *" can store pointers of any type, and pointers can be cast to void and then back to the original type without information loss. But they are a distinct type, and not necessarily interchangeable with other pointer types.
Does this matter the vast majority of the time? No. Is it C standard lawyer nitpickery of the most annoying kind? Yes, of course. But the C89 standard is this way precisely because there were some systems for which this kind of nitpicking *did* matter.
But yes, where you wrote: "It seems to me that (type *)
NULL is still a perfectly good choice of value for such a parameter." is correct. I should have distinguished that in my original reply.
A small nit-pick...
Posted Mar 19, 2008 22:27 UTC (Wed) by dw (subscriber, #12017)
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"The idea of a "void *" being generic is that variables of type "void *" can store pointers of
any type, and pointers can be cast to void and then back to the original type without
information loss."
As far as I remember it is illegal to convert between void* and any function pointer type in
ANSI C; POSIX' specification of dlsym() actually relies on what is essentially a vendor
extension to work for function pointers.
A small nit-pick...
Posted Mar 19, 2008 22:52 UTC (Wed) by vmole (guest, #111)
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Oops, you're correct about that. I just looked in Plauger and Brodie's "Standard C" (which is not the standard, but I think we can trust them), and they agree: it's *object* pointers that can be intraconverted with void pointers.
But the hilarious thing is this:
The types _pointer_to_char_, _pointer_to_signed_char_, _pointer_to_unsigned_char_, and _pointer_to_void_ all
share the same representation.
So "(void *) 0" is interchangeable with "(char *) 0", but not "0" or "(int *) 0".
A small nit-pick...
Posted Mar 19, 2008 23:15 UTC (Wed) by nix (subscriber, #2304)
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This is surely related to the aliasing rules, which also have a similar
special hole allowing aliasing of of void * and char *, but not of
pointers of any other distinct types.