The VMI virtualization interface
Posted Mar 16, 2006 18:11 UTC (Thu) by iabervon
Parent article: The VMI virtualization interface
Would it be possible to reorganize UML as a VMI ROM, such that it actually runs a regular kernel, catches the request for the ROM (which the regular kernel isn't expecting to provide), return the UML routines, and have it work essentially the same as the current design.
I suspect that it would be really helpful for debugging if you could run an unmodified kernel binary as a UML kernel.
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