Quote of the week

Quote of the week

The compiler needs to know at compile time all possible variations of that class.

If this is true, please explain to me how on earth the compiler manages to compile this code:

 
foo.h: 
class Foo { 
public: 
  virtual void f(); 
}; 
 
foo.cpp: 
#include "foo.h" 
void Foo::f() {} 
 
bar.h: 
#include "foo.h" 
class Bar : public Foo { 
public: 
  void f(); 
}; 
 
bar.cpp: 
#include "bar.h" 
void Bar::f() {} 

cc -o foo.o -c foo.cpp 
cc -o bar.o -c bar.cpp 
cc -o foobar foo.o bar.o